0=4+5x+2x^2

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Solution for 0=4+5x+2x^2 equation: 



0=4+5x+2x^2

We move all terms to the left:

0-(4+5x+2x^2)=0

We add all the numbers together, and all the variables

-(4+5x+2x^2)=0

We get rid of parentheses

-2x^2-5x-4=0

a = -2; b = -5; c = -4;
Δ = b2-4ac
Δ = -52-4·(-2)·(-4)
Δ = -7
Delta is less than zero, so there is no solution for the equation

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